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5n^2+9n-10000=0
a = 5; b = 9; c = -10000;
Δ = b2-4ac
Δ = 92-4·5·(-10000)
Δ = 200081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{200081}}{2*5}=\frac{-9-\sqrt{200081}}{10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{200081}}{2*5}=\frac{-9+\sqrt{200081}}{10} $
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